Note: Use the minimum number of binary digits needed for the representation (Truncate unnecessary trailing 0s). computeBinary(5) ==> "0101" (incorrect) computeBinary(5) ==> "101" (correct)
Recurse through the input number to break it down into its binary format.1. Check the input number. If it's less than 2, return its string equivalent.2. Else, return the concatenation of two recursive calls, i.e. input/2 and input%2 as input paramters.
